Tamilnadu Samacheer Kalvi 7th Science Solutions Term 1 Chapter 1 Measurement
Samacheer Kalvi 7th Science Measurement Textual Evaluation
BOOK EXERCISE
I. Choose the appropriate answer:
Question 1.
Which of the following is a derived unit?
(a) mass
(b) time
(c) area
(d) length
Answer:
(c) area
Question
2.
Which of the following is correct?
(a) 1L=lcc
(b) 1L= l0cc
(c) 1L= l00cc
(d) 1L= l000cc
Answer:
(d) 1L = 1000cc
Question 3.
SI unit of density is
(a) kg/m2
(b) kg/m3
(c) kg/m
(d) g/m3
Answer:
(b) kg/m3
Question 4.
Two spheres have equal mass and volume in the ratio 2:1. The ratio of their
density is
(a) 1:2
(b) 2:1
(c) 4:1
(d) 1:4
Answer:
(b) 2:1
Question 5.
Light year is the unit of
(a) Distance
(b) time
(c) density
(d) both length and time
Answer:
(a) Distance
II. Fill in the blanks:
1.Volume of irregularly shaped objects
are measured using the law of Archimedes
2.One cubic metre is equal
to 10,00,000
or 1066 cubic centimetre.
3.Density of mercury is 13,600 kg/m3
4.One astronomical unit is equal to 1.496×1011m
5.The area of a leaf can be measured
using a
graph
sheet
III. State whether the following
statements are true or false.
Question 1.
The region covered by the boundary of the plane figure is called its volume.
Answer: (False) Correct
statement: The region covered by the boundary of plane figure is called its
area.
Question 2.
Volume of liquids can be found using measuring containers. Answer:
True
Question 3.
Water is denser than kerosene.
Answer:
True
Question 4.
A ball of iron floats in mercury.
Answer:
True
Question 5.
A substance which contains less number of molecules per unit volume is said to
be denser.
Answer:
False.
Correct statement: A substance which
contains more number of molecules per unit volume is said to be denser.
IV. Match the items in column – I to
the items in column – II :
Question 1.
i. Area (a)light year
ii.Distance (b)m3
iii.Density (c)m2
iv.Volume (d)kg
V.Mass (e)kg/ m3
Question
2.
i.Area (a)g / cm3
ii.Length (b)measuring
jar
iii.Density (c)amount of a substance
iv.Volume (d)rope
V.Mass (e)plane
figures
V. Arrange the following in correct
sequence :
Question 1.
1L, 100 cc, 10 L, 10 cc
Answer:
10 cc, 100 cc, 1L, 10L
Question 2.
Copper, Aluminium, Gold,
Iron
Answer:
Aluminium, Iron,
Copper, Gold
VI. Use the analogy to fill in the
blank:
Question 1.
Area: M2 :: Volume : _________
Answer:
M3
Question 2.
Liquid : Litre :: Solid : _________
Answer:
cm3
Question 3.
Water: Kerosene :: ______ : Aluminium
Answer:
Iron
VII. Assertion and reason type
questions:
Mark the correct choice as
(a) Both assertion and reason are true
and reason is the correct explanation of assertion
(b) Both assertion and reason are true, but reason is not the correct
explanation of assertion
(c) If assertion is true but reason is false
(d) Assertion is false but reason is true
Question 1.
Assertion (A) : Volume of a stone is found using a measuring
cylinder.
Reason (R) : Stone is an irregularly shaped object.
Answer:
(a) If both assertion and reason are true and reason is the correct explanation
of assertion
Question 2.
Assertion (A) : Wood floats in water.
Reason (R) : Water is a transparent liquid.
Answer:
(b) If both assertion and reason are true, but reason is not the correct
explanation of assertion
Correct explanation: Density of water is more than the density of wood.
Question 3.
Assertion (A) : Iron ball sinks in water.
Reason (R) : Water is denser than iron.
Answer:
(b) If both assertion and reason are true, but reason is not the correct
explanation of assertion
Correct explanation : Density of iron is more than that of water.
VIII. Give very short answer:
Question 1.
Name some of the derived quantities.
Answer:
Area, volume, density.
Question 2.
Give the value of one light year.
Answer:
One light year = 9.46 x 1015m
Question 3.
Write down the formula used to find the volume of a cylinder.
Answer:
Volume of a cylinder = πr2 h
Question 4.
Give the formula to find the density of objects.
Answer:
Density = mass(m)
volume(v)
Question 5.
Name the liquid in which an iron ball sinks.
Answer:
Iron ball sinks in water. The density of an iron ball is more than that of
water so it sinks in water.
Question 6.
Name the unit used to measure the distance between celestial objects.
Answer:
Astronomical unit and light year are the units used to measure the distance
between celestial objects.
Question 7.
What is the density of gold?
Answer:
Density of gold is 19,300 kg/m3
IX. Give Short Answer.
Question 1.
What are derived quantities?
Answer:
The physical quantities which can be obtained by multiplying, dividing or by
mathematically combining the fundamental quantities are known as derived
quantities.
(or)
The physical quantities which are expressed is terms of fundamental quantities
are called
Question 2.
Distinguish between the volume of liquid and capacity of a container.
Volume
of liquid
1.Volume is the amount of space taken
up by a liquid
It is measured in cubic units
It is calculated by multiplying the
length, width and height of an object.
Capacity
of a container
Capacity is the measure of an objects
ability to hold a substance like solid, liquid or gas
It is measured in litres,
gallons, pounds,etc.,
It’s measurement is cc or ml
Question 3.
Define the density of objects.
Answer:
Density of a substance is defined as the mass of the substance contained in
unit volume
Question 4.
What is one light year?
Answer:
One light year is the distance travelled by light in vacuum during the period
of one year.
1 Light year = 9.46 x 1015m.
Question 5.
Define one astronomical unit?
Answer:
One astronomical unit is defined as the average distance between the earth and
the sun.
1 AU = 1.496 5 106km = 1.496 × 1011m.
X. Answer In detail.
Question 1.
Describe the graphical method to find the area of an irregularly shaped plane
figure.
Answer:
To find the area of an irregularly shaped plane figure, we have to use graph
paper.
Place a piece of paper with an
irregular shape on a graph paper and draw its outline.
To find the area enclosed by the
outline, count the number of squares inside it (M).
You will find that some squares lie
partially inside the outline.
Count a square only if half (p) or more
of it (N) lies inside the outline.
Finally count the number of squares,
that are less than half. Let it be
For the shape in figure we have the
following:
M = 50
N = 7
P = 4
Q = 4
Now, the approximate area of the can be calculated using the following formula.
Area of the leaf = M+(3/4) N + (1/2)
P+1/4 Qsq.cm
= 52 + 5.25 = 58.25 sq.mm = 0.5825 sq.cm
Question 2.
How will you determine the density of a stone using a measuring jar?
Answer:
Determination of density of a stone using a measuring cylinder.
In order to determine the density of a
solid, we must know the mass and volume of the stone.
The mass of the stone is determined by
a physical balance very accurately. Let it be ‘m’ grams.
In order to find the volume, take a
measuring cylinder and pour in it some water.
Record the volume of water from the
graduations marked on measuring cylinder. Let it be 40 cm3.
Now tie the given stone to a fine
thread and lower it gently in the measuring cylinder, such that it is
completely immersed in water.
Record the new level of water. Let it
be 60 cm3
∴Volume of the solid = (60-40) cm3
= 20 cm3 = V cm3 (assume)
Knowing the mass and the volume of the stone, the density can be calculate by
the formula:
Density = Mass
Volume
XI. Questions based on Higher er
Thinking skills:
Question 1.
There are three spheres A, B, C as shown below :
Answer:
Sphere A and B are made of the same
material. Sphere C is made of a different material. Spheres A and C have equal
radii. The radius of sphere B is half that of A. Density of A is double that of
C.
Question 2.
Now answer the following questions:
Find the ratio of masses of spheres A
and B.
Find the ratio of volumes of spheres A
and B.
Find the ratio of masses of spheres A
and C.
Answer:
i. Ratio
of masses of spheres A and B
MA : MB
D × VA : D
× VB
Let the
mass of sphere A = MA
Let the mass of sphere B = MB
Mass = Density × Volume
MA = DA × VA
MB = DB × VB (Density
is same)
Volume of Sphere A =4/3πr3
ii. Ratio of volumes of spheres A and
B
VA : VB
8 : 1 (As mass is directly proportional to volume)
iii. Ratio of masses of spheres A and
C.
[∴ Density of A is double that of C ]
XII. Numerical problems:
Question 1.
A circular disc has a radius 10 cm. Find the area of the disc in m2. (Use n =
3.14)
Answer:
Given radius = 10 cm = 0.1m
π= 3.14
Area of a circular disc A = ?
Formula : Area of a circle A = πr2
= 3.14 × 0.1 × 0.1
Solution : A = 0.0314 m2
Question 2.
The dimension of a school playground is 800 m x 500 m. Find the area of the
ground.
Answer:
Given :The dimension of a school
Playground = l x b = 800 m x 500 m
Formula :Area of the ground A = l x
b
= 800 x 500 = 4,00,000
A = 4,00,000 m2
Question 3.
Two spheres of same size are made from copper and iron respectively. Find the
ratio between their masses. Density of copper 8,900 kg/m and iron 7,800 kg/m3
Answer:
Given : Density Copper Dc = 8900 kg/m3
Density of Iron D1 =
7800 kg/m3
Volume of Copper sphere = Volume of Iron sphere
To find : Ratio of Masses of Copper (MC) and
Iron (MI)
Solution: Mass = Density x Volume
MC = DC x
V, M1 = D1 x
V
MC =
8900 V, M1 =
7,800 V
MC = M1
8900 V : 7800 V
= 1.14: 1
Question 4.
A liquid having a mass of 250 g fills a space of lOOOcc. Find
the density of the liquid.
Answer:
Given : Mass of a liquid M = 250 g
Volume V = l000cc
Density of the liquid D = ?
Solution: Density of the liquid = 0.25
g/cc
Question 5.
A sphere of radius 1cm is made from silver. If the mass of the sphere is 33 g,
find the density of silver (Take π = 3.14)
Answer:
Given : radius of a sphere r = 1cm
Volume of the sphere V = ?
Mass of the sphere M = 33 g
Density of silver D = ?
Solution: Density of silver sphere = 7.889 g/cc.
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